## electrochemistry previous year questions

It includes questions asked in previous year exams, questions provided by Kendriya Vidyalaya KV schools, DoE, Delhi government school, Navodaya Vidyalaya samiti NVS and other government and private schools in India and abroad that are affiliated to CBSE, New Delhi. (2) $\lambda_{\mathrm{C}}=\lambda_{\infty}+(\mathrm{B}) \sqrt{\mathrm{C}}$ Electrolytic cells are those in which a non-spontaneous reaction is controlled by an external source of electric current. Introduction to galvanic/voltaic cells. Previous Year & Mock Questions. Download India's Best Exam Preparation App. Shikha Munjal. JEE Main Previous Year Papers Questions With Solutions Chemistry Redox Reactions and Electrochemistry. Here we have covered Important Questions on Electrochemistry for Class 12 Chemistry subject.. Chemistry Important Questions Class 12 are given below.. (4) X = Fe, Y = Zn (2), (1) $6250 \mathrm{Sm}^{2} \mathrm{mol}^{-1}$, (2) $6.25 \times 10^{-4} \mathrm{S} \mathrm{m}^{2} \mathrm{mol}^{-1}$, (3) $625 \times 10^{-4} \mathrm{S} \mathrm{m}^{2} \mathrm{mol}^{-1}$, (4) $62.5 \mathrm{S} \mathrm{m}^{2} \mathrm{mol}^{-1}$, Q. It has anelectrical potential of 1.1 V. Students can easily download these solutions in PDF format for free. (1)Zn         (2) Pb         (3) Cr        (4) Cu. (3) $\mathrm{p}\left(\mathrm{H}_{2}\right)=1$ atm and $\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}$ (c) Corrosion of iron can be minimized by forming an impermeable barrier at its surface. Multiple Choice Questions (Type-I) Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Chemistry. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Hence, $\mathrm{MnO}_{4}^{-}$ is stronger oxidising agent. JEE-Mains (online) 2015 The mass of copper deposited at the cathode is : Galvanization is applying a coating of :-, How long (approximate) should water be electrolysed by passing through 100, Nuclear Chemistry – JEE Main Previous Year Questions with Solutions, JEE Main Previous Year Questions Topicwise, Atomic Structure Revision Video – Class 11, JEE, NEET, Ferromagnetic Substance – Magnetism & Matters | Class 12 Physics Notes, Paramagnetic Substances – Magnetism & Matters | Class 12 Physics Notes, Forces || Newton Laws Of motion || Class 11 Physics Notes. AIEEE 2010 $\mathrm{Zn}\left|\mathrm{Zn}^{2+}(1 \mathrm{M}) \| \mathrm{Cu}^{2+}(1 \mathrm{M})\right| \mathrm{Cu}$, of potential 1.1 V. When $\mathrm{E}_{\mathrm{ext}}<1.1 \mathrm{V}$ and $\mathrm{E}_{\mathrm{ext}}>1.1 \mathrm{V}$ , respectively electrons flow from : Here we have given Plus Two Chemistry Chapter Wise Questions and Answers Chapter 3 Electrochemistry. (1) X = Zn, Y = Ni Plus Two Chemistry Chapter Wise Previous Year Question Paper - Kerala Board Previous Year Question Paper Class 12 Chemistry with Solutions are now available for download in PDF format. Since $\mathrm{Cr}^{+3}$ is having least reducing potential, so Cr is the best Reducing agent. $\mathrm{E}^{\circ}=\frac{3 \times-0.036+2 \times 0.439}{1}=0.77 \Rightarrow \mathrm{A}$. The cell that converts the chemical energy liberatedas a result of redox reaction to electrical energy is called a Daniel cell. The MCQs are based on only Electrochemistry. Answer & Solution : Electrochemistry. (1) anode to cathode in both cases Here you can get the link to Download Bharathiar University Question Papers. A variable, opposite external potential $\left(\mathrm{E}_{\mathrm{ext}}\right)$ is applied to the cell 9. $\mathrm{Zn}\left|\mathrm{Zn}^{2+}(1 \mathrm{M}) \| \mathrm{Cu}^{2+}(1 \mathrm{M})\right| \mathrm{Cu}$, of potential 1.1 V. When $\mathrm{E}_{\mathrm{ext}}<1.1 \mathrm{V}$ and $\mathrm{E}_{\mathrm{ext}}>1.1 \mathrm{V}$ , respectively electrons flow from : (2) anode to cathode and cathode to anode, (4) cathode to anode and anode to cathode, Q. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Two Faraday of electricity is passed through a solution of $\mathrm{CuSO}_{4}$. (1)Zn         (2) Pb         (3) Cr        (4) Cu Given : (4) (4) $62.5 \mathrm{S} \mathrm{m}^{2} \mathrm{mol}^{-1}$ $\mathrm{Fe}^{+3}_{(\mathrm{aq})}+\mathrm{e}^{-} \longrightarrow \mathrm{Fe}^{+2}_{(\mathrm{aq})}$ will be :-, (1) 0.770 V (2) –0.27 V (3) –0.072 V (4) 0.385 V, $\mathrm{E}^{\circ}=\frac{3 \times-0.036+2 \times 0.439}{1}=0.77 \Rightarrow \mathrm{A}$, Q. Download Electrochemistry Previous Year Solved Questions PDF, 1. (d) remove adsorbed oxygen from the electrode surface. 5. NEET preparation series 2020 ELECTROCHEMISTRY(previous NEET year questions) - Duration: 16:13. (2). S1: Conductivity always increases with decrease in the concentration of electrolyte. $966 \times 10^{3}=4 \times 96500 \times \mathrm{E} \Rightarrow \mathrm{E}=2.5 \mathrm{V}$, $\frac{2}{3} \mathrm{Al}_{2} \mathrm{O}_{3} \longrightarrow \frac{4}{3} \mathrm{Al}+\mathrm{O}_{2}, \mathrm{AG}=+966 \mathrm{KJ} \mathrm{mol}^{-1}$ The potential difference needed for electrolytic reduction of $\mathrm{Al}_{2} \mathrm{O}_{3}$ at $500^{\circ} \mathrm{C}$ is at least :-, (1) 5.0 V      (2) 4.5 V       (3) 3.0 V         (4) 2.5 V, $966 \times 10^{3}=4 \times 96500 \times \mathrm{E} \Rightarrow \mathrm{E}=2.5 \mathrm{V}$, Q. It will help you to … (a) Corrosion of iron can be minimized by forming contact with another metal with a higher reduction potential. (1) Galvanization is a method of preventing rust by applying zinc coating. So 0.1 F will deposit (0.1/2) moles of Ni. AIEEE 2011 (4) I- only How many moles of Ni will be deposited at the cathode? Electrochemistry. Fe2+ (aq) + Ag+ (aq) → Fe3+ (aq) + Ag(s), Given that E°Ag+/Ag = x V; E°Fe2+/Fe = y V; E°Fe3+/Fe = z V, Adding equations (i) and (iii) and subtracting (ii) from it, we get, 11. Electrochemistry… The specific conductance of the solution is 1.3 S $\mathrm{m}^{-1}$. (4) 6. $\mathrm{E}_{\mathrm{Fe}^{-3} / \mathrm{Fe}}^{\circ}=-0.036 \mathrm{V}, \quad \mathrm{E}_{\mathrm{Fe}^{-2} / \mathrm{Fe}}^{\circ}=-0.439 \mathrm{V}$. (2) $\mathrm{Cl}^{-}, \mathrm{Br}^{-}$ and $\mathrm{I}^{-}$ IIT JEE. The correct order of E0M2+/M values with negative sign for the four successive elements Cr, Mn, Fe and Co is. $\frac{2}{3} \mathrm{Al}_{2} \mathrm{O}_{3} \longrightarrow \frac{4}{3} \mathrm{Al}+\mathrm{O}_{2}, \mathrm{AG}=+966 \mathrm{KJ} \mathrm{mol}^{-1}$ The potential difference needed for electrolytic reduction of $\mathrm{Al}_{2} \mathrm{O}_{3}$ at $500^{\circ} \mathrm{C}$ is at least :- Redox reaction from dissolving zinc in copper sulfate. Molar Conductivity increases with decrease in concentration. Electrochemistry's Previous Year Questions with solutions of Chemistry from JEE Main subject wise and chapter wise with solutions Q. 13. For what concentration of Ag+ will the EMF of te given cell be zero at 25 C .If the concentration of Cu2+ is 0.1 M. EoAg+ = 0.80v and Eo Cu2+ = 0.34 V Please answer. (3) $\mathrm{Cr}^{3+}$ Find all the NEET Chemistry important questions from the chapter Electrochemistry with solutions to perform better in the exam here. The electrolyte and the electrode comprise an electrode compartment. 4.5. Generally, electrochemistry covers weight age of 2-3 questions in every … 15 ratings • 1 review. AIEEE 2009 Class 10 Class 12. SHOW SOLUTION MCQs are the questions in which students of JEE can gain marks or can lose marks very easily. Plus Two Chemistry Chapter Wise Previous Questions Chapter 3 Electrochemistry is part of Kerala Plus Two Chemistry Chapter Wise Previous Year Questions and Answers. In a hydrogen-oxygen fuel cell, combustion of hydrogen occurs to (a) generate heat (b) create a potential difference between the two electrodes (c) produce high purity water (d) remove adsorbed oxygen from the electrode surface. Hi, viewers today we are sharing Electrochemistry Question Bank PDF for JEE Main 2018.This practice set contains set of 100 questions.In this post, we are providing 100 question with solutions which are very useful for JEE Main, UPSEE and all other state Engineering entrance exam.You can download the PDF from the link given below. (Atomic weight of B = 10.8 u) JEE-Mains 2017 The standard reduction potentials for $\mathrm{Zn}^{2+} / \mathrm{Zn}, \mathrm{Ni}^{2+} / \mathrm{Ni}$ and $\mathrm{Fe}^{2+} / \mathrm{Fe}$ are $-0.76,-0.23$ and – 0.44 V respectively. Here you can get Class 12 Important Questions Chemistry based on NCERT Text book for Class XII.Chemistry Class 12 Important Questions are very helpful to score high marks in board exams. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Free PDF download of Important Questions for CBSE Class 12 Chemistry Chapter 3 - Electrochemistry prepared by expert Chemistry teachers from latest edition of CBSE(NCERT) books. 628k watch mins. $\mathrm{Fe}^{+3}_{(\mathrm{aq})}+\mathrm{e}^{-} \longrightarrow \mathrm{Fe}^{+2}_{(\mathrm{aq})}$ will be :- Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Electrochemistry JEE Main previous year questions and solutions are given in this article. Based on the data given above, strongest oxidising agent will be : Higher the SRP, stronger will be oxidising agent. (1) Cl– JEE-Mains 2013 (4) 6.4 hours The questions given here give you an idea about what type of questions to expect from this topic. The reactions carried out using the process of electrochemistry are energy effective and less polluting. The important topics include electrochemical cell, electrolytic cell, Faraday’s laws of electrolysis, Kohlrausch’s Law, electrode potential, etc. For students of class 12 who are looking to give a good performance for their board exams and also to perform well for competitive exams like JEE and more, it is important that they prepare well with the help of important questions which tend to repeat over the years. an electrolyte. The reaction $\mathrm{X}+\mathrm{Y}^{+2} \rightarrow \mathrm{X}^{2+}+\mathrm{Y}$ will be spontaneous when For a cell reaction involving a two-electron change, the standard e.m.f. amperes current so that the oxygen released can completely burn 27.66 g of diborane ? (4) $\mathrm{Cl}^{-}$ The correct option among the following is. The maximum age limit is 30 years as on December 31, of the year of admission for students belonging to reserved category. Fact. Class 12 Chemistry Electrochemistry have different set of questions. Q. Resistance of 0.2 M solution of an electrolyte is $50 \Omega$. 2015 – Very Short Answer Type Questions [1 Mark] 1. SHOW SOLUTION Practicing JEE Main chapter wise questions of Chemistry will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas. Two Faraday of electricity is passed through a solution of $\mathrm{CuSO}_{4}$. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. (4) $\mathrm{p}\left(\mathrm{H}_{2}\right)=1$ atm and $\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}$ If the standard electrode potential for a cell is 2 V at 300 K, the equilibrium constant (K) for the reaction, at 300 K is approximately (R = 8 J K–1 mol–1, F = 96500 C mol–1), 14. Previous Year Papers. JEE-Mains (online) 2015 info@entrancei.com Vivek SK. English. (1) Answer: Ag + + e – ——> Ag(s) 1 Faraday of … amperes current so that the oxygen released can completely burn 27.66 g of diborane ? 1.Conductivity (unit Siemen’s S) is directly proportional to area of the vessel and the concentration of the solution in it and is inversely proportional to the length of the vessel then the unit of the constant of proportionality is (2002) Conductivity (unit Siemen’s S) is directly proportional to the area of the vessel and the concentration of the solution in it and is inversely proportional to the length of the vessel then the unit of the constant of proportionality is, 3. JEE Advanced Previous Year Questions of Chemistry with Solutions are available at eSaral. Based on the data given above, strongest oxidising agent will be : 011-47340170 . Download the PDF Question Papers Free for off line practice and view the Solutions online. Free courses. Solving the last years' question papers can help you understand the difficulty level of the paper, type of questions asked in the exam, analyze your performance, etc. Login. Register online for Chemistry tuition on Vedantu.com to score more marks in CBSE board examination. Practicing JEE Advanced Previous Year Papers Questions of Chemistry will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas. HSSLIVE Chemistry Plus Two Question Paper is provided below with answers as per the guidelines of the Kerala board marking scheme. 16:13. (2) X = Ni, Y = Fe They need to choose the correct option. SHOW SOLUTION mass of Cu = 63.5 amu) Conductivity increases with an increase in concentration. SHOW SOLUTION SHOW SOLUTION In this Class, Shikha Munjal will cover some Important Questions and previous year's questions on Electrochemistry. A-1, Acharya Nikatan, Mayur Vihar, Phase-1, Central Market, New Delhi-110091. Save. Q. SHOW SOLUTION Scroll below to select your subject or search year wise question papers. (3) $\mathrm{Mn}^{2+}$ In a hydrogen-oxygen fuel cell, the combustion of hydrogen occurs because of the difference in potential between two electrodes. Since $\mathrm{Cr}^{+3}$ is having least reducing potential, so Cr is the best Reducing agent. The standard Gibbs energy for the given cell reaction in kJ mol–1 at 298 K is, Zn(s) + Cu2+ (aq) → Zn2+(aq) + Cu(s), E ° = 2 V at 298 K (Faraday’s constant, F = 96000 C mol–1) (a) –192. (1) 2g         (2) 127 g          (3) 0 g          (4) 63.5 g Fact, (1) $\lambda_{\mathrm{C}}=\lambda_{\infty}-(\mathrm{B}) \sqrt{\mathrm{C}}$, (2) $\lambda_{\mathrm{C}}=\lambda_{\infty}+(\mathrm{B}) \sqrt{\mathrm{C}}$, (3) $\lambda_{\mathrm{C}}=\lambda_{\infty}+(\mathrm{B}) \mathrm{C}$, (4) $\lambda_{\mathrm{C}}=\lambda_{\infty}-(\mathrm{B}) \mathrm{C}$, Q. SHOW SOLUTION Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. SHOW SOLUTION The reaction $\mathrm{X}+\mathrm{Y}^{+2} \rightarrow \mathrm{X}^{2+}+\mathrm{Y}$ will be spontaneous when. The value of standard electrode potential for the change. (1) 5.0 V      (2) 4.5 V       (3) 3.0 V         (4) 2.5 V (3) $\mathrm{Br}^{-}$ and $\mathrm{I}^{-}$ SHOW SOLUTION (1) $\lambda_{\mathrm{C}}=\lambda_{\infty}-(\mathrm{B}) \sqrt{\mathrm{C}}$ The unit tests, chapter wise solved papers, important questions, and questions asked in previous year exams are included in CBSE test papers and CBSE practice papers with solution and answer keys. (1) Hence, $\mathrm{MnO}_{4}^{-}$ is stronger oxidising agent. Free Question Bank for NEET Chemistry Electrochemistry. Given : 1. If resistance of the 0.4M solution of the same electrolyte is $260 \Omega$, its molar conductivity is :-, The reduction potential of hydrogen half-cell will be negative if :-, The standard reduction potentials for $\mathrm{Zn}^{2+} / \mathrm{Zn}, \mathrm{Ni}^{2+} / \mathrm{Ni}$ and $\mathrm{Fe}^{2+} / \mathrm{Fe}$ are $-0.76,-0.23$ and – 0.44 V respectively. (1) (3) cathode to anode in both cases The equivalent conductance of NaCl at concentration C and at infinite dilution are $\lambda_{\mathrm{C}}$ and $\lambda_{\infty}$ , respectively. (3) X = Ni, Y = Zn 5. Practicing JEE Main chapter wise questions of Chemistry will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas. 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The value of standard electrode potential for the change. OTP has been sent to your mobile number and is valid for one hour (2) $6.25 \times 10^{-4} \mathrm{S} \mathrm{m}^{2} \mathrm{mol}^{-1}$ A solution of Ni(NO3 )2 is electrolysed between platinum electrodes using 0.1 Faraday electricity. SHOW SOLUTION Practice: Electrochemistry questions. (1)0.8 hours An electrochemical cell consists of two metallic conductors known as electrodes in contact with an ionic conductor i.e. Chapterwise Previous Years Questions 2019-10 (PYQs) with Solutions for Class 6 to Class 12 Maths, Science, English, Social Science, and Hindi prepared by expert teachers in PDF format to download on LearnCBSE.in and increase your chances to score higher marks in your CBSE Exams. Here we have given Plus Two Chemistry Chapter Wise Questions and Answers Chapter 3 Electrochemistry. $\mathrm{E}_{\mathrm{Fe}^{-3} / \mathrm{Fe}}^{\circ}=-0.036 \mathrm{V}, \quad \mathrm{E}_{\mathrm{Fe}^{-2} / \mathrm{Fe}}^{\circ}=-0.439 \mathrm{V}$. The negative values for standard electrode potential decrease except for Mn because of the stable d5 configuration, across the first transition series. Important Questions for CBSE Class 12 Chemistry Electrochemistry Previous Years’ Questions. (1) And also provide detail solutions, Sir , I want to purchase previous years IIT JEE Chapter wise. (4) cathode to anode and anode to cathode When during electrolysis of a solution of AgN03 9650 coulombs of charge pass through the electroplating bath, the mass of silver deposited on the cathode will be, 15. These questions are One marks questions with given multiple choices. Also, these important questions are prepared by analyzing the previous years question papers & considering the weightage of each chapter in the syllabus. How long (approximate) should water be electrolysed by passing through 100 (3) $\lambda_{\mathrm{C}}=\lambda_{\infty}+(\mathrm{B}) \mathrm{C}$ The correct relationship between $\lambda_{\mathrm{C}}$ and $\lambda_{\infty}$ is given as: If φ denotes reduction potential, then which is true? Electrochemistry - MCQs on Previous Year Questions. The correct relationship between $\lambda_{\mathrm{C}}$ and $\lambda_{\infty}$ is given as: At 298 K, the standard reduction potentials are 1.51 V for $\mathrm{MnO}_{4}-| \mathrm{Mn}^{2+}$ , 1.36 V for $\mathrm{Cl}_{2} | \mathrm{Cl}^{-}$, 1.07 V for $\mathrm{Br}_{2} | \mathrm{Br}^{-},$ and $0.54 \mathrm{V}$ for $\mathrm{I}_{2} | \mathrm{I}^{-} .$ At $\mathrm{pH}=3$, permanganate is expected to oxidize $\left(\frac{\mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{V}\right):-$, A variable, opposite external potential $\left(\mathrm{E}_{\mathrm{ext}}\right)$ is applied to the cell. Q. (4) $\lambda_{\mathrm{C}}=\lambda_{\infty}-(\mathrm{B}) \mathrm{C}$ S2: Molar conductivity always increases with decrease in the concentration of electrolyte. This course has a variety of MCQs from different examinations from previous year papers. The Gibbs energy for the decomposition of $\mathrm{Al}_{2} \mathrm{O}_{3}$ at $500^{\circ} \mathrm{C}$ is as follows : (1) $6250 \mathrm{Sm}^{2} \mathrm{mol}^{-1}$ Electrochemistry What's 'n' in the equation: E°(cell) = 0.0591/n log Kc All the important topics will be discussed in detail and would be helpful for aspirants preparing for the IIT JEE exam. Q. Galvanization is applying a coating of :- As far as the JEE exam is concerned, electrochemistry is an important topic. Class 12 Marks/Qualification Students must have passed class 12 board exam or an equivalent exam from a recognized board with at least five mandatory subjects like Physics, Chemistry, Biology, English and an elective subject. For spontaneous reaction $\mathrm{E}^{\circ}>0 \mathrm{so}(\mathrm{A})$, For spontaneous reaction $\mathrm{E}^{\circ}>0 \mathrm{so}(\mathrm{A})$. Electrochemistry refers to the branch of chemistry which deals with the flow of electricity and the chemistry behind it. Students who are preparing for JAM 2021 Exam must be looking for the IIT JAM Previous Year Question Papers to boost up their preparation. Chemistry Questions with solution, you have any book for this pl confirm & cost of book, Plz bro questions are dope but i need clr solutions even i cant solve it, Need some more questions plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz, Download India's Leading JEE | NEET | Class 9,10 Exam preparation app, Electrochemistry – JEE Main Previous Year Questions with Solutions. (2) $\mathrm{Mn}^{2+}$ (4) $\mathrm{MnO}_{4}^{-}$ (3) $625 \times 10^{-4} \mathrm{S} \mathrm{m}^{2} \mathrm{mol}^{-1}$ $2 \mathrm{F}=2 \mathrm{eq}=1$ mole $=63.5 \mathrm{gm}$, (1) 2g         (2) 127 g          (3) 0 g          (4) 63.5 g, $2 \mathrm{F}=2 \mathrm{eq}=1$ mole $=63.5 \mathrm{gm}$. JEE-Mains 2015 (1), (1) $\mathrm{p}\left(\mathrm{H}_{2}\right)=2 \operatorname{atm}\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}$, (2) $\mathrm{p}\left(\mathrm{H}_{2}\right)=2$ atm and $\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}$, (3) $\mathrm{p}\left(\mathrm{H}_{2}\right)=1$ atm and $\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}$, (4) $\mathrm{p}\left(\mathrm{H}_{2}\right)=1$ atm and $\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}$, Q. Hence option (c) is the answer. (1) $\mathrm{Cl}^{-}$ and $\mathrm{Br}^{-}$ The Gibbs energy for the decomposition of $\mathrm{Al}_{2} \mathrm{O}_{3}$ at $500^{\circ} \mathrm{C}$ is as follows : Resistance of 0.2 M solution of an electrolyte is $50 \Omega$. There are many more useful educational material which the students can download in pdf format and use them for studies. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Download Electrochemistry Previous Year Solved Questions PDF. Enter OTP. AIEEE 2011/JEE-MAIN 2014 If resistance of the 0.4M solution of the same electrolyte is $260 \Omega$, its molar conductivity is :- MCQ (Previous Year Questions) - Electrochemistry (Level 2) MCQ of Electrochemistry. Electrodes and voltage of Galvanic cell. JEE Main Maths Previous Year Questions With Solutions on Electrochemistry Solution: Corrosion of iron can be minimized by forming an impermeable barrier at its surface. In a hydrogen-oxygen fuel cell, combustion of hydrogen occurs to, (b) create a potential difference between the two electrodes. JEE Main Previous Year Solved Questions on Electrochemistry . 8. Zinc acts as a sacrificial metal. (3), (1) $\mathrm{Cl}^{-}$ and $\mathrm{Br}^{-}$, (2) $\mathrm{Cl}^{-}, \mathrm{Br}^{-}$ and $\mathrm{I}^{-}$, (3) $\mathrm{Br}^{-}$ and $\mathrm{I}^{-}$, Q. Our faculty team after a thorough analysis of the last years examination question papers and the latest examination jee advanced format, have framed these questions paper. (2) $\mathrm{p}\left(\mathrm{H}_{2}\right)=2$ atm and $\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}$ SHOW SOLUTION Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. The branch of chemistry that deals with the chemical changes produced by electric current and the electricity generation by chemical changes is known as electrochemistry. (2) 3.2 hours The session will be conducted in Hindi and the notes will be … Corrosion of iron can be minimized by forming an impermeable barrier at its surface. (4) Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Currently only available for. Kerala Plus Two Chemistry Chapter Wise Previous Questions and Answers Chapter 3 Electrochemistry Question 1. JEE Main Previous Year Papers Questions of Chemistry with Solutions are available at eSaral. The specific conductance of the solution is 1.3 S $\mathrm{m}^{-1}$. Please answer this question. (1) 0.770 V (2) –0.27 V (3) –0.072 V (4) 0.385 V (2) $\mathrm{Cr}^{3+}$ NATIONAL ELIGIBILITY CUM ENTRANCE TEST(UG) – 2020 [NEET(UG)-2020] will be conducted by the Central Board of Secondary Education (CBSE), for admission to MBBS/BDS Courses in India in Medical/Dental Colleges run with the approval of Medical Council of India/Dental Council of India under the Union Ministry of Health and Family Welfare, Government of India except for the institutions … (1)Cr Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. JEE-Mains 2014 Given Question 1. JEE-Mains 2018 EMF of a cell in terms of reduction potential of its left and right electrodes is, Ecell = Reduction potential of the cathode – Reduction potential of the anode, 7. Kerala Plus Two Chemistry Chapter Wise Questions and Answers Chapter 3 Electrochemistry Plus Two Chemistry Electrochemistry One Mark Questions and Answers. Find chapter notes of Electrochemistry including important concepts, formulae and previous years' questions related for JEE Main and JEE Advanced 2019. Calculate the standard cell potential (in V) of the cell in which the following reaction takes place. Galvanization is applying a coating of. The reduction potential of hydrogen half-cell will be negative if :- The equilibrium constant of the reaction at 25°C will be. How much charge in Faraday is required for the reduction of 1 mol of Ag + to Ag? Q. Download JEE Advanced Chemistry Practice Sample Paper Answer and Solution. 2. (3) 1.6 hours (1) $\mathrm{p}\left(\mathrm{H}_{2}\right)=2 \operatorname{atm}\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}$ This test is Rated positive by 87% students preparing for Class 12.This MCQ test is related to Class 12 syllabus, prepared by Class 12 teachers. Download Previous Year Question Papers.. Daniel cell. The amount of PbSO4 electrolyzed in g during the process is [Molar mass of PbSO4 = 303 g mol–1], Total number of moles of PbSO4 = 0.05/2 = 0.025, 10. Learners at any stage of their preparations will be benefited from this course. MHT-CET Previous year questions Chapter-wise Chemistry Electrochemistry MHT-CET PCM PYQs MHT-CET Previous year questions Chapter-wise Chemistry Electrochemistry Time limit: 0 The anodic half-cell of lead-acid battery is recharged using electricity of 0.05 Faraday. Galvanization is the process of applying a protective zinc coating of steel or iron, to prevent rusting. Please add questions of 2019 and 2020 as well, Still more questions are required plz add questions of 2019 and 20 questions in it…. SHOW SOLUTION Komali Mam 4,442 views. The equivalent conductance of NaCl at concentration C and at infinite dilution are $\lambda_{\mathrm{C}}$ and $\lambda_{\infty}$ , respectively. 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